Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks

Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks

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Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin2 θ

iv) sin (90o – θ) cos (90o – θ) = tan θ/ (1 + tan2 θ) - Noon Academy

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सिद्ध कीजिए कि `(sin (90^(@)-theta)cos (90^(@)-theta))/(tan theta)=1-sin^(2) theta`