Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A

Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A

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Sin(90-A) /1-tanA+cos(90-A) /1-cotA=sinaA+cosA

Prove the following: (tan(90^0-A)cotA)/(cos e c^2A)-cos^2A=0

Prove that: tan (90° - A) cot A/ cosec^2 A - cos^2 A = 0

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If `A+B = 90^@`; prove that `sqrt((tanA tanB+tanA cotB)/(sinA secB

SOLVED: If A + B = 90°, then prove that √(tanA.tanB + tanA