∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

EXAMPLE 12 Triangle ABC is isosceles with `AB = AC = 7.5 cm and BC

ABC is an isosceles triangle with ab is equal to AC is equal to

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

Ex 9.1, 8 - ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm

Triangle ABC is isosceles with AB=AC=7.5cm and BC=9cm. The height

Fig 11.25 △ABC is isosceles with AB=AC=7.5 cm and BC=9 cm (Fig

ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height

ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

ΔABC is isosceles with AB=AC=7cm and BC=9cm. The height AD from A

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex

ABC is an isosceles triangle with AB = AC and BC = 16 cm and

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex